Veteran forward Bobby Portis has signed a deal with the Milwaukee Bucks. Portis’ deal is for a reported two years, and was able to sign after being waived by the New York Knicks.
The Athletic’s Shams Charania reported the news on Saturday via Twitter.
Free agent Bobby Portis has agreed to a deal with the Milwaukee Bucks, sources tell @TheAthleticNBA @Stadium.
— Shams Charania (@ShamsCharania) November 21, 2020
The Bucks will be Portis’ fourth team since joining the league out of Arkansas in 2015. He was waived by the Knicks on Thursday, taking only three days to find a new team.
In 66 games, Portis averaged 10.1 points and 5.1 rebounds during the 2019-2020 season. He was not eligible to play in the NBA bubble in Orlando, due to the Knicks not qualifying. His best scoring season came in 2018-2019, when he scored 14.3 points a game.
The Bucks, a contender in the East, hope Portis can reach that high again.
Featured Image courtesy of David Liam Kyle/Getty Images
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