Outfielder Mookie Betts and the Los Angels Dodgers are close to terms on an extension that will be worth between $350-$400 million. This is according to WEEI in Boston.
REPORT: Betts, Dodgers Close to Massive Extension 💰💰💰
WEEI in Boston is reporting the Dodgers and Mookie Betts are close to a 10+ year extension valued between $350-$400M. pic.twitter.com/tYWpIVTfyG
— MLB on uSTADIUM (@uSTADIUM_MLB) July 22, 2020
If Betts extension is worth between $350-$400M he will be the second-highest paid player in the MLB. If his deal is worth more than $355 million he will pass Mike Trout for the highest annual salary in the league.
The Los Angeles Dodgers acquired Betts from the Boston Red Sox in a three-team trade that involved David Price coming to L.A., Alex Verdugo headed to Boston, and Kenta Maeda going to Minnesota.
Betts made his debut for the Red Sox in 2014. During his time with the team, he won Wilson Defensive Player of the Year (2016), is a three-time Silver Slugger and four-time Golden Glove Winner.
In 2018 Betts was the AL Batting Champion and won league MVP. He also was vital to the Red Sox World Series victory that season. This past season Betts was named to the All-MLB Second Team.